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ksyubelaya
@ksyubelaya
August 2022
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Не выполняя построения,найдите координаты точек пересечения параболы y=x2-14 и прямой x+y=6
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shyrynt
Х^2-14=6-хХ^2+х-20=0Х1=-5Х2=4;=> у1=11 координаты (-5;11)У2 = 2 координаты (2;4)
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