Не выполняя построения,найдите координаты точки пересечения графиков линейных функций:
а)у=4х+9 и у=6х-5
б)у=16х-7 и у=21х+8
в)у=10х-7 и у=5
г)у=0,1х и у=14
а) у = 4х + 9 и у = 6х - 5
4x + 9 = 6x - 5
4x - 6x = -5 - 9
-2x = -14
x = 7
y = 4 · 7 + 9 = 37
y = 6 · 7 - 5 = 37
(7 ; 37)
б) y = 16x - 7 и y = 21x + 8
16x - 7 = 21x + 8
16x - 21x = 8 + 7
-5x = 15
x = -3
y = 16 · (-3) - 7 = - 48 - 7 = -55
y = 21 · (-3) + 8 = - 63 + 8 = -55
(-3 ; -55)
в) y = 10x - 7 и y=5
10x - 7 = 5
10x = 12
x = 1,2
y = 10 · 1,2 - 7 = 12 - 7 = 5
y = 5
(1,2 ; 5)
г) y = 0,1x и y = 14
0,1x = 14
x = 140
y = 0,1 · 140 = 14
y = 14
(140 ; 14)
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Verified answer
а) у = 4х + 9 и у = 6х - 5
4x + 9 = 6x - 5
4x - 6x = -5 - 9
-2x = -14
x = 7
y = 4 · 7 + 9 = 37
y = 6 · 7 - 5 = 37
(7 ; 37)
б) y = 16x - 7 и y = 21x + 8
16x - 7 = 21x + 8
16x - 21x = 8 + 7
-5x = 15
x = -3
y = 16 · (-3) - 7 = - 48 - 7 = -55
y = 21 · (-3) + 8 = - 63 + 8 = -55
(-3 ; -55)
в) y = 10x - 7 и y=5
10x - 7 = 5
10x = 12
x = 1,2
y = 10 · 1,2 - 7 = 12 - 7 = 5
y = 5
(1,2 ; 5)
г) y = 0,1x и y = 14
0,1x = 14
x = 140
y = 0,1 · 140 = 14
y = 14
(140 ; 14)