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annakisa553
@annakisa553
August 2021
1
18
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НЕВЕРОЯТНО МНОГО БАЛЛОВ!
Задания(слева от вас, т.е. 1-й вариант).
1 - а, 1 - б.
2 - ну, вот это тождество.
3 - а.
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Answers & Comments
arslan7171
2cos²(18π+5π)/24cos²(18π-5π)/24=(2cos(18π/12+5π/12)/2cos(18π/12-5π/12)/2)*0.5(2
cos(18π/12+5π/12)/2cos(18π/12-5π/12)/2)=
(cos18π/12+cos5π/12)*0.5(cos18π/12+cos5π/12)=0.5(
cos18π/12+cos5π/12)
²=0.5(cos(π+π/2)+
2)cos68cos22-sin3sin87+sin25cos20.5=cos(90-22)cos22-sin3sin(90-3)+sin25cos20.5=sin22cos22-sin3cos3+sin25cos20.5=0.5sin44+0.5sin6-sin25cos20.5=0.5·2sin25cos38-sin25cos20.5=sin25(cos38+cos20.5)=sin25(2cos58.5/2cos17.5/2
(sin34cos16-sin(90-34)sin16)/
(sin(90-82)+cos82cos10)=
(sin34cos16-cos34sin16)/
(cos82+cos82cos10)=
sin(34-16)/cos82(1+cos10)=sin18/cos82(1+cos10) здесь явно описка
3)a (1+sin2α)/(1-sin2α)*cos²(π/4+α)/sin²(π/4+α)=(1+sin2α)/(1-sin2α)/(1+cos2(π/4+α))/(1-cos2(π/4+α))=(1+sin2α)/(1-sin2α)*(1+cos(π/2+2α)/(1-cos(π/2+α)=(1+sin2α)/(1-sin2α)*(1-sin2α)/(1+sin2α)=1
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Answers & Comments
2cos²(18π+5π)/24cos²(18π-5π)/24=(2cos(18π/12+5π/12)/2cos(18π/12-5π/12)/2)*0.5(2cos(18π/12+5π/12)/2cos(18π/12-5π/12)/2)=
(cos18π/12+cos5π/12)*0.5(cos18π/12+cos5π/12)=0.5(cos18π/12+cos5π/12)²=0.5(cos(π+π/2)+
2)cos68cos22-sin3sin87+sin25cos20.5=cos(90-22)cos22-sin3sin(90-3)+sin25cos20.5=sin22cos22-sin3cos3+sin25cos20.5=0.5sin44+0.5sin6-sin25cos20.5=0.5·2sin25cos38-sin25cos20.5=sin25(cos38+cos20.5)=sin25(2cos58.5/2cos17.5/2
(sin34cos16-sin(90-34)sin16)/(sin(90-82)+cos82cos10)=
(sin34cos16-cos34sin16)/(cos82+cos82cos10)=
sin(34-16)/cos82(1+cos10)=sin18/cos82(1+cos10) здесь явно описка
3)a (1+sin2α)/(1-sin2α)*cos²(π/4+α)/sin²(π/4+α)=(1+sin2α)/(1-sin2α)/(1+cos2(π/4+α))/(1-cos2(π/4+α))=(1+sin2α)/(1-sin2α)*(1+cos(π/2+2α)/(1-cos(π/2+α)=(1+sin2α)/(1-sin2α)*(1-sin2α)/(1+sin2α)=1