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bekenovak
@bekenovak
August 2022
1
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нод чисел 75,512 помагите
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Nastya171167
75 = 3*5*5
512 = 2*2*2*2*2*2*2*2*2
числа 75 и 512 взаимно-простые
НОД(75, 512) = 1
1 votes
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bekenovak
спасибо
Nastya171167
пожалуйста
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Answers & Comments
512 = 2*2*2*2*2*2*2*2*2
числа 75 и 512 взаимно-простые
НОД(75, 512) = 1