Номер 328 б Упростите. Created by irishka1609. algebra-ru

Номер 328 б Упростите...

August 2022 1 16 Report

Номер 328 б
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leushbogdan

((sina+cosa/sina)/(1+sin2a/cosa))-ctg2a=((sin2a+cosa)/sina)/((cosa+sin2a)/cosa))-ctg2a=((sin2a+cosa)/sina)*(cosa/(cosa+sin2a))-ctg2a=(1/(sin3a+sinacosa))-ct

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