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DHAcity
@DHAcity
July 2022
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Номер 4 с д по з..........................
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Д) (2х-1)(5х-2)=0
2х-1=0 или 5х-2=0
2х=1 5х=2
х₁=1/2=0,5 х₂=2/5=0,4
е) (4х-1)(х+2)=0
4х-1=0 или х+2=0
4х=1 х₂= -2
х₁=1/4=0,25
ж) (3х+3)(2х-1)=0
3х+3=0 или 2х-1=0
3х= -3 2х=1
х₁= -1 х₂= 1/2 = 0,5
з) (3х+2)(2х+1)=0
3х+2=0 или 2х+1=0
3х= -2 2х= -1
х₁= -2/3 х₂= -1/2 = -0,5
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Answers & Comments
Verified answer
Д) (2х-1)(5х-2)=02х-1=0 или 5х-2=0
2х=1 5х=2
х₁=1/2=0,5 х₂=2/5=0,4
е) (4х-1)(х+2)=0
4х-1=0 или х+2=0
4х=1 х₂= -2
х₁=1/4=0,25
ж) (3х+3)(2х-1)=0
3х+3=0 или 2х-1=0
3х= -3 2х=1
х₁= -1 х₂= 1/2 = 0,5
з) (3х+2)(2х+1)=0
3х+2=0 или 2х+1=0
3х= -2 2х= -1
х₁= -2/3 х₂= -1/2 = -0,5