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8dariadaria8
@8dariadaria8
July 2022
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altowa1
5) f (x)=6x^2-x^3
f'(x)=12x-3x^2>0
3x(4-x)> 0
3x> 0
x> 0
4-x> 0
-x>-4
x> 4
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8dariadaria8
спасибо а 6?))
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Answers & Comments
f'(x)=12x-3x^2>0
3x(4-x)> 0
3x> 0
x> 0
4-x> 0
-x>-4
x> 4