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Ulker99
@Ulker99
August 2022
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Номер 5 срочно нужно...
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dasdasfa
К=y'(x); y'(x)=(5^x-25xln5)'=5^xln5-25ln5
касательная параллельна оси х, тогда к=0
5^xln5-25ln5=0; ln5(5^x-25)=0; 5^x-25=0; 5^x=5^2; x=2
ответ.А
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Answers & Comments
касательная параллельна оси х, тогда к=0
5^xln5-25ln5=0; ln5(5^x-25)=0; 5^x-25=0; 5^x=5^2; x=2
ответ.А