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Анн04ка2000
@Анн04ка2000
July 2022
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номер 629)Помогите пожалуйста.
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Mydrый
(2x)^4/(4x)^2=16x^4/16x^2=x^2 (-2/3)^2=4/9
(9y)^3/(3y)^5=3/y^2 3:(1/3)^2=3:1/9=3*9=27
(2a)^3(2a)^2/(4a)^2=32a^5/16a^2=2a^3 2(-0.1)^3=-0.002
(4c)^5*(2c)^6/(4c)^6=(2c)^6/4c (2*-1/2)^6/4*-1/2=(-1)^6/-2=-0.5=-1/2
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mmb1
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Решениеееееееееееееееееееееееееееееееее
б) при у=1/3 3/(1/3)^2=3*9=27
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Answers & Comments
(9y)^3/(3y)^5=3/y^2 3:(1/3)^2=3:1/9=3*9=27
(2a)^3(2a)^2/(4a)^2=32a^5/16a^2=2a^3 2(-0.1)^3=-0.002
(4c)^5*(2c)^6/(4c)^6=(2c)^6/4c (2*-1/2)^6/4*-1/2=(-1)^6/-2=-0.5=-1/2
Verified answer
Решениеееееееееееееееееееееееееееееееееб) при у=1/3 3/(1/3)^2=3*9=27