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Pilika17
@Pilika17
June 2022
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номер 680!!!!ПОМОГИТЕ
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vsem2privet
2HgO = 2Hg + O2
n(HgO)/n(O2) = 2/1
n(HgO)=m(HgO)/M(HgO)=4.34/217=0,02 моль
0.02моль/n(О2)=2/1
n(О2)=0,01 моль
V(О2)= Vm*n(O2)=22,4л/моль*0,01моль=0,224 л
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toystroy
1)n(HgO)=4.34/217=0.02 моль
2)n(O2)=0.01 моль
3)V(O2)=0.01×22.4=0.224 л
0 votes
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Answers & Comments
n(HgO)/n(O2) = 2/1
n(HgO)=m(HgO)/M(HgO)=4.34/217=0,02 моль
0.02моль/n(О2)=2/1
n(О2)=0,01 моль
V(О2)= Vm*n(O2)=22,4л/моль*0,01моль=0,224 л
2)n(O2)=0.01 моль
3)V(O2)=0.01×22.4=0.224 л