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Novoolga1999
@Novoolga1999
July 2022
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номер 8.25 под буквой б, только не списывайте с решебника
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qnyqiny
( 9/х * (2+ 1/х) - 9/х * (2- 1/х) ) / (2- 1/х)(2+ 1/х)=
(18/х + 9/х^2 - 18/x + 9/x^2 ) / (4-1/x^2) =
(18/x^2) / (4-1/x^2)
преобразуем и подставим значение х, получим
0,2 ^ -1 = (2/10) ^ -1 = (10/2)^1=5
18/5^2 /(4-1/5^2)= 18/25 / (4-1/25) =18/25 : 99/25 = 18/25 * 25/99 = 18/99 =2/11
ответ 2/11
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Answers & Comments
(18/х + 9/х^2 - 18/x + 9/x^2 ) / (4-1/x^2) =
(18/x^2) / (4-1/x^2)
преобразуем и подставим значение х, получим
0,2 ^ -1 = (2/10) ^ -1 = (10/2)^1=5
18/5^2 /(4-1/5^2)= 18/25 / (4-1/25) =18/25 : 99/25 = 18/25 * 25/99 = 18/99 =2/11
ответ 2/11