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dimafaldin
@dimafaldin
June 2022
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номер 8помогите решить
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sangers1959
Verified answer
Ax²+c=0
x²=-c/a
Так как х²≥0 ⇒
-с/a≥0
Ответ: (c≤0 a>0) (c≥0 a<0).
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Answers & Comments
Verified answer
Ax²+c=0x²=-c/a
Так как х²≥0 ⇒
-с/a≥0
Ответ: (c≤0 a>0) (c≥0 a<0).