Номера: 269, 270. Заранее спасибо!. Created by tea74. algebra-ru

Номера: 269, 270. Заранее спасибо!...

tea74 @tea74

July 2022 1 46 Report

Номера: 269, 270. Заранее спасибо!

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sedinalana

Verified answer

269
а)(x+5)/(2x+6)>0
x=-5 x=-3
x∈(-∞;-5) U (-3;∞)
б)(6-x)(2x-9)/(x+5)>0
x=6 x=4,5 x=-5
   + _ + _
---------------(-5)----------------(4,5)-------------(6)-------------------
x∈(-∞;-5) U (4,5;6)
в)
(3-2x)(5+3x)/(3x-6)<0
x=1,5 x=-5/3 x=2
+ _ + _
---------------(-5/3)----------------(1,5)-------------(2)-------------------
x∈(-5/3;1,5) U (2;∞)
г)
(7x+1)(11x+2)/(13x-4)>0
x=-1/7 x=-2/11 x=4/13
_ + _    +
---------------(-2/11)----------------(-1/7)-------------(4/13)-------------------
x∈(-2/11;-1/7) U (4/13;∞)
270
а)(3-4x)/(2-x)≥0
x=0,75 x=2
x∈(-∞;0,75] U (2;∞)
б)(6-8x)²/(2x+7)≤0
x=0,75 x=-3,5
   _ + +
------------------(-3,5)----------[0,75]-------------
x∈(-∞;-3,5) U {0,75}
в)(5x-0,2)/(2x+0,3)≥0
x=0,04 x=-0,15
x∈(-∞;-0,15) U [0,04;∞)
г)(x-4)(2x+7)/(x+8)≥0
x=4 x=-3,5 x=-8
_ + _ +
---------------(-8)----------------[-3,5]-------------[4]-------------------
x∈(-8;-3,5] U [4;∞)
д)(1-x)(3x+2)/(2x+3)≤0
x=1 x=-2/3 x=-1,5
+    _ + _
---------------(-1,5)----------------[-2/3]-------------[1]-------------------
x∈(-1,5;-2/3] U [1;∞)
е)(6x-1)(3x-2)/(x+4)≤0
x=1/6 x=2/3 x=-4
_ + _ +
---------------(-4)----------------[1/6]-------------[2/3]-------------------
x∈(-∞;-4) U [1/6;2/3]

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