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capslooker
@capslooker
July 2022
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номера 4, 5, 6 на другие можно решение не писать (45 бал)
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IrkaShevko
Verified answer
Если надо разложить на множители:
4) x³ + x² - x - 1 = x³ - x + x² - 1 = x(x² - 1) + (x² - 1) = (x+1)(x² - 1) = (x+1)²(x-1)
5) (xy)³ + 64 = (xy)³ + 4³ = (xy + 4)(x²y² - 4xy + 16)
6) 8m³ + n⁹ = (2m)³ + (n³)³ = (2m + n³)(4m² - 2mn³ + n⁶)
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Answers & Comments
Verified answer
Если надо разложить на множители:4) x³ + x² - x - 1 = x³ - x + x² - 1 = x(x² - 1) + (x² - 1) = (x+1)(x² - 1) = (x+1)²(x-1)
5) (xy)³ + 64 = (xy)³ + 4³ = (xy + 4)(x²y² - 4xy + 16)
6) 8m³ + n⁹ = (2m)³ + (n³)³ = (2m + n³)(4m² - 2mn³ + n⁶)