zhenyaM2002

Verified answer

№3.
1))2а+b + 2a²+ab = 1 * (2a+b)  + a*(2a+b) = (1+a)(2a+b)

2)3a+3a² -b-ab = 3a(1+a) - b(1+a)= (3a-b)(1+a)

3)2x²-3x+4ax -6a = (2x²+4ax) + (-3x-6a) = 
= 2x(x+2a) -3(x+2a) = (x+2a)(2x-3)

4) x²y²+xy +axy+a = xy(xy+1) + a(xy+1) = (xy+a)(xy+1)

vicper1957z

Verified answer

1)=2a(1+a)+b(1+a)=(1+a)(2a+b)
2)=3a(1+a)-b(1+a)=(1+a)(3a-b)
3)=x(2x-3)+2a(2x-3)=(2x-3)(x+2a)
4)= xy(xy+1)+a(xy+1)=(xy+1)(xy+a)