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ruhsoragulamova
@ruhsoragulamova
November 2021
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ну помогитите ну пожалуста задание 5
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sangers1959
Verified answer
A)
1) y=14-2x x∈(-∞;+∞).
2) y=x/(x+2) x+2≠0 x≠-2 ⇒x∈(-∞;-2)U(-2;+∞).
b)
y=(2x+5)/3 x∈[-1;5]
y₁=(2*(-1)+5)/3=(-2+5)/3=3/3=1
y₂=(2*5+5)/3=(10+5)/3=15/3=5 ⇒
y∈[1;5].
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Answers & Comments
Verified answer
A)1) y=14-2x x∈(-∞;+∞).
2) y=x/(x+2) x+2≠0 x≠-2 ⇒x∈(-∞;-2)U(-2;+∞).
b)
y=(2x+5)/3 x∈[-1;5]
y₁=(2*(-1)+5)/3=(-2+5)/3=3/3=1
y₂=(2*5+5)/3=(10+5)/3=15/3=5 ⇒
y∈[1;5].