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Direx1337
@Direx1337
August 2021
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Нужна помощь :_( Очень
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magicmasha
^1/2 - это корень квадратный ;
1) а) 26^1/2 и 5; 26^1/2>25^1/2; 26^1/2>5;
б)6*3^1/2 и 5*4^1/2; (36*3)^1/2 и (25*4)^1/2;
108^1/2>100^1/2; 6*3^1/2>5*4^1/2;
2) а) (0,36*121)^1/2=0,6*11= 6,6;
б)(80*2/10)^1/2= 16^1/2=4;
в) (216^1/2)/(6^1/2)=(216/6)^1/2=36^1/2=6;
г) ((-8)^4)^1/2=(-8)^2=64;
3) а) (7^1/2-3^1/2)^2= (7-2*7^1/2*3^1/2+3)= 10-2*21^1/2;
б) (10^1/2-8)(10^1/2+8)=10-64=-54;
в) 2*50^1/2-3*8^1/2+2^1/2= 2*5*2^1/2-3*2*2^1/2+2^1/2=
10*2^1/2-6*2^1/2+2^1/2= 5*2^1/2;
4) (18х^3)=3х*(2х)^1/2 при х>=0;
5) (а^2-5в^2)/(а+в*5^1/2)=
((а-в*5^1/2)(а+в*5^1/2))/(а+в*5^1/2)= а-в*5^1/2;
6) тут затрудняюсь:
а) 3/21^1/2= ((21^1/2)/3)^-1;
б) 1/(5-7^1/2)= (5-7^1/2)^-1;
может быть так?
2 votes
Thanks 1
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Answers & Comments
1) а) 26^1/2 и 5; 26^1/2>25^1/2; 26^1/2>5;
б)6*3^1/2 и 5*4^1/2; (36*3)^1/2 и (25*4)^1/2;
108^1/2>100^1/2; 6*3^1/2>5*4^1/2;
2) а) (0,36*121)^1/2=0,6*11= 6,6;
б)(80*2/10)^1/2= 16^1/2=4;
в) (216^1/2)/(6^1/2)=(216/6)^1/2=36^1/2=6;
г) ((-8)^4)^1/2=(-8)^2=64;
3) а) (7^1/2-3^1/2)^2= (7-2*7^1/2*3^1/2+3)= 10-2*21^1/2;
б) (10^1/2-8)(10^1/2+8)=10-64=-54;
в) 2*50^1/2-3*8^1/2+2^1/2= 2*5*2^1/2-3*2*2^1/2+2^1/2=
10*2^1/2-6*2^1/2+2^1/2= 5*2^1/2;
4) (18х^3)=3х*(2х)^1/2 при х>=0;
5) (а^2-5в^2)/(а+в*5^1/2)=
((а-в*5^1/2)(а+в*5^1/2))/(а+в*5^1/2)= а-в*5^1/2;
6) тут затрудняюсь:
а) 3/21^1/2= ((21^1/2)/3)^-1;
б) 1/(5-7^1/2)= (5-7^1/2)^-1;
может быть так?