Нужна помощь срочно!!!!!!. Created by snizanaprihodko071. algebra-ru

Нужна помощь срочно!!!!!!...

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Ответ:

$a=6\cdot 10^{n+1}\ \ ,\ \ \ b=3\cdot 10^{n}\\\\\\a+b=6\cdot 10^{n}\cdot 10+3\cdot 10^{n}=3\cdot 10^{n}\cdot (20+1)=63\cdot 10^{n}\\\\a-b=6\cdot 10^{n}\cdot 10-3\cdot 10^{n}=3\cdot 10^{n}\cdot (20-1)=57\cdot 10^{n}\\\\a\cdot b=6\cdot 10^{n}\cdot 10\cdot 3\cdot 10^{n}=180\cdot 10^{2n}\\\\a:b=\dfrac{6\cdot 10^{n}\cdot 10}{3\cdot 10^{n}}=2\cdot 10=20$

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snizanaprihodko071 Спасибо

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Verified answer

Відповідь:

a + b = 10^n*63;

a - b = 10^n*57;

a * b = 18*10^(2n+1);

a / b = 20;

Пояснення:

a = 6*10^n+1

b = 3*10^n

a + b = 6*10^(n+1) + 3*10^n = 10^n(60 + 3) = 10^n*63;

a - b = 6*10^(n+1) - 3*10^n = 10^n(60 - 3) = 10^n*57;

a * b = 6*10^(n+1) * 3*10^n = 18*10^(2n+1);

a / b = 6*10^(n+1) / 3*10^n = 10 * 2 = 20;

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