НУЖНА ПОМОЩЬ СРОЧНО!!!!!!!!!!!!!!!!!!!!. Created by maref1203. algebra-ru

НУЖНА ПОМОЩЬ СРОЧНО!!!!!!!!!!!!!!!!!!!!...

maref1203 @maref1203

August 2022 2 4 Report

НУЖНА ПОМОЩЬ
СРОЧНО!!!!!!!!!!!!!!!!!!!!

sedinalana F`(x)=2cosx/4*(-sinx/4)-2sinx/4*cosx/4=-4sinx/4*cosx/4=-2sinx/2
-2sinx/2=0
sinx/2=0
x/2=πn
x=2πn,n∈z

2 votes Thanks 1

ПрофиЗнания f`(x)=2cosx/4*(-sinx/4)-2sinx/4*cosx/4=-4sinx/4*cosx/4=-2sinx/2

f'=2cos x/4 * (-sin x/4) - 2sin x/4 * cos x/4= -2sinx/4cosx/4-2sinx/4cosx/4 =
=-4sinx/4cosx/4 = -2sinx/2

f'=0
-2sinx/2=0
sin x/2 =0
x/2=πn
x=2πn , n∈Z

0 votes Thanks 0

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