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Ann0897
@Ann0897
July 2022
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Нужна помощь!
В схеме реакции HNO3=H2O+NO2+O2
расставьте коэффициенты методом электронного баланса
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kedr57
4HNO3=2H2O+4NO2+O2
N
⁺⁵+1e=N⁺⁴
2O⁻²-4e=O2
6 votes
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Answers & Comments
N⁺⁵+1e=N⁺⁴
2O⁻²-4e=O2