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Катя987654321
@Катя987654321
July 2021
2
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Нужно 3,4,5,6
Помогите пожалуйста:3
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LilitKit
3)а) (4у-0,5)(4у+0,5)
б)(а+5b)^2
4) 25-10x+x^2-2.5x-x^2=0
12.5x=25
x=2
5)a)
б)
в)
6)a)
б)(b+8-2b)(b+8+2b)=(8-b)(8+3b)
в)
1 votes
Thanks 1
I1ll1make1you1smile
Решение:
3
16y^2 - 0,25 = (4y - 0,5)(4y+0,5)
a^2 + 10 ab + 25b^2 = (a +5b)^2
4
( 5 - x)^2 - x(2,5 + x) = 0
25 - 10x + x^2 - 2,5x - x^2 = 0
- 12,5x + 25 = 0 | (- 1)
12,5x - 25 = 0
12,5x = 25
x = 25/12,5
x = 2
5
(2a - b^2)(2a+b^2) = 4a^2 - b^4
(x-6x^3)^2 = x^2 - 12x^3 + 36x^6
(y + b)^2 (y - b)^2 = (y^2 - b^2)^2 = y^2 - 2yb^2 + b^4
6
1/81 * a^2 - 0,09c^4 = (1/9 * a - 0,3)(1/9 *a +0,3)
(b+8)^2 - 4b^2 = ((b+8) - 4b)((b+8) - 4b)
a^9 - b^3 = (a^3)^3 - b^3 = ((a^3 - b)((a^3)^2) + (a^3)b + b^2)
1 votes
Thanks 0
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Answers & Comments
б)(а+5b)^2
4) 25-10x+x^2-2.5x-x^2=0
12.5x=25
x=2
5)a)
б)
в)
6)a)
б)(b+8-2b)(b+8+2b)=(8-b)(8+3b)
в)
3
16y^2 - 0,25 = (4y - 0,5)(4y+0,5)
a^2 + 10 ab + 25b^2 = (a +5b)^2
4
( 5 - x)^2 - x(2,5 + x) = 0
25 - 10x + x^2 - 2,5x - x^2 = 0
- 12,5x + 25 = 0 | (- 1)
12,5x - 25 = 0
12,5x = 25
x = 25/12,5
x = 2
5
(2a - b^2)(2a+b^2) = 4a^2 - b^4
(x-6x^3)^2 = x^2 - 12x^3 + 36x^6
(y + b)^2 (y - b)^2 = (y^2 - b^2)^2 = y^2 - 2yb^2 + b^4
6
1/81 * a^2 - 0,09c^4 = (1/9 * a - 0,3)(1/9 *a +0,3)
(b+8)^2 - 4b^2 = ((b+8) - 4b)((b+8) - 4b)
a^9 - b^3 = (a^3)^3 - b^3 = ((a^3 - b)((a^3)^2) + (a^3)b + b^2)