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Gasterbayter36
@Gasterbayter36
August 2022
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Нужно объяснение к заданию C1 и C2.
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MizoriesKun
C1. ОДЗ 9-х²≥0 -3≤ х ≤3
х∈[-3 ;3]
x²+3x-4 >0 (x²+3x-4 ≠0 )
D=9+16=25
x=(-3+5)/2=1
x=(-3-5)/2=-4
+ - +
____-4 _________1_______
x∈(-∞;-4)∪(1;+∞)
объединяем обе ОДЗ
x∈ (1;3]
С2 f(3-х)=2х²+3х-1
3-х= t ⇒x =3-t
f(t)= 2(3-t)² +3*(3-t) -1=2*(9-6t+t²)+9-3t-1=18-12t+2t²+9-3t-1 =
= 2t²-15t+26
f(x)= 2x²-15x+26
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Answers & Comments
x²+3x-4 >0 (x²+3x-4 ≠0 )
D=9+16=25
x=(-3+5)/2=1
x=(-3-5)/2=-4
+ - +
____-4 _________1_______ x∈(-∞;-4)∪(1;+∞)
объединяем обе ОДЗ x∈ (1;3]
С2 f(3-х)=2х²+3х-1
3-х= t ⇒x =3-t
f(t)= 2(3-t)² +3*(3-t) -1=2*(9-6t+t²)+9-3t-1=18-12t+2t²+9-3t-1 =
= 2t²-15t+26
f(x)= 2x²-15x+26