2Al+6HCl=2AlCl3+H2
AlCl3+3КOH=Al(OH)3+3КCl
2Al(OH)3⇒ Al2O3 + 3H2O
Al2O3+2NaOH+3H2O=2Na[Al(Oh)4]
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Verified answer
2Al+6HCl=2AlCl3+H2
AlCl3+3КOH=Al(OH)3+3КCl
2Al(OH)3⇒ Al2O3 + 3H2O
Al2O3+2NaOH+3H2O=2Na[Al(Oh)4]