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viktor101211
@viktor101211
May 2021
2
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Нужно подробное решение на 1 и 2 номер
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яВиктория
1 а) 4+27=31
б) (36+64):100+27=100:100+27=28
2. х2+44=165
х2=121
х=11, -11
1 votes
Thanks 1
yakushsasha
1.
а)2^2+3^3=4+27=31;Ответ:31
б) (6^2+4^3) : 10^2+3^3 -по действиям:
1)6^2+4^3=36+64=100
2)100 : 10^2=100:100=1
3)1+3^3=1+27=28
Ответ:28
2.
X^2+44=165;
X^2=165-44;
X^2=121;
X=11.
Ответ: X=11
1 votes
Thanks 1
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Answers & Comments
б) (36+64):100+27=100:100+27=28
2. х2+44=165
х2=121
х=11, -11
а)2^2+3^3=4+27=31;Ответ:31
б) (6^2+4^3) : 10^2+3^3 -по действиям:
1)6^2+4^3=36+64=100
2)100 : 10^2=100:100=1
3)1+3^3=1+27=28
Ответ:28
2.
X^2+44=165;
X^2=165-44;
X^2=121;
X=11.
Ответ: X=11