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Бензол (CH3Cl, AlCl3) → X1 (2Br2, hv) → X2 (изб. KOH(водн.)) → X3 ([Ag(NH3)2]OH) → X4 → C6H5COOH
Бензол (CH3Cl, AlCl3) → X1 (2Br2, hv) → X2 (изб. KOH(водн.)) → X3 ([Ag(NH3)2]OH) → X4 → C6H5COOH
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Ответ:
C6H6+CH3Cl=C6H5CH3+HCl
C6H5CH3 +3Br2 = C6H5Br3 +3HBr
C6H5Br3 + KOH = C6H5OH+ KBr
C6H5OH + [Ag(NH3)2]OH] = C6H5COOH +Ag2+NH3 +H2O
Объяснение: