Нужно решить цепочку,щедрое вознаграждение
CH4 -> C2H2 -> C2H4 + CO2 -> (C6H10O5)n -> C6H12O6 -> C2H5OH -> CH3COOH -> CH2ClCOOH -> CH2NH2COOH
CH4 -> C2H2 -> C2H4 + CO2 -> (C6H10O5)n -> C6H12O6 -> C2H5OH -> CH3COOH -> CH2ClCOOH -> CH2NH2COOH
Answers & Comments
C2H2+H2=C2H4
C2H4+3O2=2CO2+2H2O
6nCO2+5nH2O=[hv]=(C6H10O5)n+6nO2
(C6H10O5)n+nH2O=nC6H12O6
C6H12O6=2C2H5OH+2CO2
5C2H5OH+4KMnO4+6H2SO4=5CH3COOH+2K2SO4+4MnSO4+11H2O
CH3COOH+Cl2=CH2(Cl)-COOH+HCl
CH2(Cl)-COOH+NH3=HCl+CH2(NH2)-COOH