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Alexkalinin19
@Alexkalinin19
July 2022
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нужно решить уравнение. срочно.
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Удачник66
Verified answer
Замена log(1/3) x = y, тогда log(x) (1/3) = 1/y
y + 2 = 3/y
y^2 + 2y - 3 = 0
(y + 3)(y - 1) = 0
y1 = log(1/3) x1 = -3, x1 = (1/3)^(-3) = 3^3 = 27
y2 = log(1/3) x2 = 1, x2 = 1/3
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Answers & Comments
Verified answer
Замена log(1/3) x = y, тогда log(x) (1/3) = 1/yy + 2 = 3/y
y^2 + 2y - 3 = 0
(y + 3)(y - 1) = 0
y1 = log(1/3) x1 = -3, x1 = (1/3)^(-3) = 3^3 = 27
y2 = log(1/3) x2 = 1, x2 = 1/3