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МиФфФа
@МиФфФа
August 2022
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Нужно решить уравнения.
х*(х-3)+4*х-12=0
х^3-4x^2+x-4=0
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Leionel
Первое
х*(х-3)+4*х-12=0
х^2-3х+4х-12=0
х^2+х-12=0
D=1-4*1(-12)=1+48=49
x1=(-1+7)/2=6/2=3
x2=(-1-7)/2=-8/2=-4
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Answers & Comments
х*(х-3)+4*х-12=0
х^2-3х+4х-12=0
х^2+х-12=0
D=1-4*1(-12)=1+48=49
x1=(-1+7)/2=6/2=3
x2=(-1-7)/2=-8/2=-4