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afonckinanatali
@afonckinanatali
August 2022
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Нужно сократить дробь...
в первом внизу там 14, а в третьем степень 2
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(√7-2)/(√14-2√2)=(√7-2)(√7+2)/(√14-2√2)(√7+2)=(7-4)/(√14*7-2√14+2√14-4√2)=3/√2*7*7-4√2)=3/(7√2-4√2)=3/3√2=1/√2=√2/2
(3+√3)/(√15+√5)=(3+√3)*(3-√3)/(√15+√5)*(3-√3)=6/(2√15+3√5-3√5)=6/2√15=3/√15
(Х²-3)/√3х+3=(х-√3)(х+√3)/√3 (х+√3)=(х-√3)/√3
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Verified answer
(√7-2)/(√14-2√2)=(√7-2)(√7+2)/(√14-2√2)(√7+2)=(7-4)/(√14*7-2√14+2√14-4√2)=3/√2*7*7-4√2)=3/(7√2-4√2)=3/3√2=1/√2=√2/2(3+√3)/(√15+√5)=(3+√3)*(3-√3)/(√15+√5)*(3-√3)=6/(2√15+3√5-3√5)=6/2√15=3/√15
(Х²-3)/√3х+3=(х-√3)(х+√3)/√3 (х+√3)=(х-√3)/√3