ω = [m(в-во) / m(р-р)]*100%
m(р-р) = m(в-во) + m(H₂O) = 10 + 390 = 400 г
ω = [10/400]*100% = 2,5%
Ответ: 2,5%
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ω = [m(в-во) / m(р-р)]*100%
m(р-р) = m(в-во) + m(H₂O) = 10 + 390 = 400 г
ω = [10/400]*100% = 2,5%
Ответ: 2,5%