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Hdhfcbc
@Hdhfcbc
July 2022
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Обчисліть кількість речовини і масу озону (О3)об'ємом 112л (н.у.).
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svetka1574
Дано: n(O3) = V / Vm = 112 / 22,4 = 5 моль
V(O3)=112 л
Vm=22,4 л/моль. m(O3) = n(O3) * M(O3) = 5 * 48 =240 г
Найти:
n(O3)
m(O3
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Answers & Comments
V(O3)=112 л
Vm=22,4 л/моль. m(O3) = n(O3) * M(O3) = 5 * 48 =240 г
Найти:
n(O3)
m(O3