дано
n(CH4) = 2 mol
-----------------
V(O2)-?
CH4+2O2-->CO2+2H2O
n(O2) = 2*2 = 4 mol
V(O2) = n(O2) * Vm = 4*22.4 = 89.6 L
ответ 89.6 л
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дано
n(CH4) = 2 mol
-----------------
V(O2)-?
CH4+2O2-->CO2+2H2O
n(O2) = 2*2 = 4 mol
V(O2) = n(O2) * Vm = 4*22.4 = 89.6 L
ответ 89.6 л