6hcl+2al=2alcl3+3h2
n(al)=m(al)/M(al)=16.2/27=0.6моль
n(h2)=3/2n(alcl3)=3/2*0.6=0.9моль
V(h2)=n(h2)*Vm=0.9*22.4=20.16л
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
6hcl+2al=2alcl3+3h2
n(al)=m(al)/M(al)=16.2/27=0.6моль
n(h2)=3/2n(alcl3)=3/2*0.6=0.9моль
V(h2)=n(h2)*Vm=0.9*22.4=20.16л