дано
n(Na2CO3) = 5 mol
------------------------------------
V(CO2)-?
Na2CO3+2HCL-->2NaCL+H2O+CO2
n(Na2CO3) = n(CO2) = 5 mol
V(CO2) = n*Vm = 5*22.4 = 112 L
ответ 112 л
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Verified answer
дано
n(Na2CO3) = 5 mol
------------------------------------
V(CO2)-?
Na2CO3+2HCL-->2NaCL+H2O+CO2
n(Na2CO3) = n(CO2) = 5 mol
V(CO2) = n*Vm = 5*22.4 = 112 L
ответ 112 л