Ответ:
2Al(OH)3 + 3H2SO4 → Al2(SO4)3 + 6H2O
M (Al(OH)3) = 78 г/моль
n (Al(OH)3) = 5*2/3 = 3,333 моль
m (Al(OH)3) = 3,333 * 78 = 260 г
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Ответ:
2Al(OH)3 + 3H2SO4 → Al2(SO4)3 + 6H2O
M (Al(OH)3) = 78 г/моль
n (Al(OH)3) = 5*2/3 = 3,333 моль
m (Al(OH)3) = 3,333 * 78 = 260 г