Ответ:
Объяснение:
Mr(Fe(OH)2) =90
W(O)= Ar(O) *n / Mr(Fe(OH)2) *100% = 16*2 / 90 *100% = 36%
Mr(Fe(OH)3) = 107
W(O) = Ar(O) *n / Mr(Fe(OH)3) *100% = 16*3 / 107 *100% = 45%
W2(O) > W1(O)
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Ответ:
Объяснение:
Mr(Fe(OH)2) =90
W(O)= Ar(O) *n / Mr(Fe(OH)2) *100% = 16*2 / 90 *100% = 36%
Mr(Fe(OH)3) = 107
W(O) = Ar(O) *n / Mr(Fe(OH)3) *100% = 16*3 / 107 *100% = 45%
W2(O) > W1(O)