Мr(Cu(OH))=64+16+1=81
ω(Cu)=Mr(Cu)/Mr(Cu(OH))*100%=64/81*100%=79,01%
ω(O)=Mr(O)/Mr(Cu(OH))*100%=16/81*100%=19,75%
ω(H)=Mr(H)/Mr(Cu(OH))*100%=1/81*100%=1,24%
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Мr(Cu(OH))=64+16+1=81
ω(Cu)=Mr(Cu)/Mr(Cu(OH))*100%=64/81*100%=79,01%
ω(O)=Mr(O)/Mr(Cu(OH))*100%=16/81*100%=19,75%
ω(H)=Mr(H)/Mr(Cu(OH))*100%=1/81*100%=1,24%