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Ответ:

Объяснение:

Mr[Ba₃(PO₄)₂=3Ar(Ba)+2×[Ar(P)+4Ar(O)]

Mr[Ba₃(PO₄)₂=3×137+2×[31+(4×16)=411+2[31+64]=411+61+128=600

ω(Ba)=3Ar(Ba)÷Mr[Ba₃(PO₄)₂=411÷600=0,685

ω%(Ba)=ω(Ba)×100%=0,685×100%=68,5%

ω(P)=2Ar(P)÷Mr[Ba₃(PO₄)₂=61÷600=0,1017

ω%(P)=ω(P)×100%=0,1017×100%=10,17%

ω(O)=8Ar(O)÷Mr[Ba₃(PO₄)₂=128÷600=0,2133

ω%(O)=ω(O)×100%=0,2133 ×100%=21,33%