Ответ:
Объяснение:
Mr(Pb(ClO2)2) = 207 + 35,5*2 + 16*4 =342
W(Pb) = Ar(Pb) *n / Mr(Pb(ClO2)2) *100% = 207 *1 / 342 *100% =60%
W(Cl) = Ar(Cl) *n / Mr(Pb(ClO2)2 *100% =35,5*2 / 342 *100% =21%
W(O) = Ar(O) *n / Mr(Pb(ClO2)2 *100% = 16*4 / 342 *100% = 19%
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Ответ:
Объяснение:
Mr(Pb(ClO2)2) = 207 + 35,5*2 + 16*4 =342
W(Pb) = Ar(Pb) *n / Mr(Pb(ClO2)2) *100% = 207 *1 / 342 *100% =60%
W(Cl) = Ar(Cl) *n / Mr(Pb(ClO2)2 *100% =35,5*2 / 342 *100% =21%
W(O) = Ar(O) *n / Mr(Pb(ClO2)2 *100% = 16*4 / 342 *100% = 19%