Ответ:
Пошаговое объяснение:
f(x) = (x^2 – 2x – 2)^5
f'(x)= 5(x²-2x-2)⁴*(x²-2x-2)' =5(x²-2x-2)⁴(2x-2) = 10(x²-2x-2)⁴(x-1)
f'(2) = 10(2²-2*2-2)⁴(2-1)=10(4 - 4 -2)*1 = -20
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Ответ:
Пошаговое объяснение:
f(x) = (x^2 – 2x – 2)^5
f'(x)= 5(x²-2x-2)⁴*(x²-2x-2)' =5(x²-2x-2)⁴(2x-2) = 10(x²-2x-2)⁴(x-1)
f'(2) = 10(2²-2*2-2)⁴(2-1)=10(4 - 4 -2)*1 = -20