Объясните и решите:
1) √2(√2-√18)=
2) √7(4√7+√28-√175)=
3)(2√6+√12)(√96-3√3)-2√72=
1) √2(√2-√18)=
2) √7(4√7+√28-√175)=
3)(2√6+√12)(√96-3√3)-2√72=
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Ответ:
Объяснение:
1) √2(√2-√18)=√2√2-√2√18=√4-√36=2-6=-4
√2(√2-√18)=√2(√2-3√2)=√2(-2√2)=-2(√2)²=-2·2=-4
2) √7(4√7+√28-√175)=√7(4√7)+√7√28-√7√175=4(√7)²+√196-√1225=
=28+14-35=7
√7(4√7+√28-√175)=√7(4√7+2√7-5√7)=√7·√7=7
3)(2√6+√12)(√96-3√3)-2√72=√12(√2+1)√3(4√2-3)-2√72=
=6(√2+1)(4√2-3)-2√72=6(8-3√2+4√2-3)-12√2=6(5+√2)-12√2=30-6√2