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neakw
@neakw
November 2021
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Объясните как это делать можно только на одном примере!
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sedinalana
Verified answer
=|sin5-sin(2π-π/6)|-|sin(π-π/6)-sin5|=|sin5-sin(-π/6)|-|sinπ/6-sin5|=
=|sin5+1/2|-|1/2-sin5|=-sin5-1/2-1/2+sin5=-1/4
-----------------------------
sin5<0,|sin5|>1/2
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Verified answer
=|sin5-sin(2π-π/6)|-|sin(π-π/6)-sin5|=|sin5-sin(-π/6)|-|sinπ/6-sin5|=
=|sin5+1/2|-|1/2-sin5|=-sin5-1/2-1/2+sin5=-1/4
-----------------------------
sin5<0,|sin5|>1/2