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Maratga1
@Maratga1
August 2022
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обьясните как решать уравнение по теореме Виета
[tex] x^{2} -37х+27=0
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sangers1959
Verified answer
Ax²+bx+c=0
x₁,₂=(-b+/-√D)/2a=(-b+/-√(b²-4ac))/2a
x²-37x+27=0 a=1 b=-37 c=27 ⇒
x₁,₂=-(-37)+/-√((-37)²-4*1*27)/2*1=(37+/-√1261)/2 ⇒
x₁=(37+√1261)/2 x₂=(37-√1261)/2.
x2-3x+2=0
D=√(3²-4*1*2)=√(9-8)=√1=1
x₁,₂=(-(-3)+/-1)2*1=(3+/-1)/2
x₁=(3+1)/2=4 x₂=(3-1)/2=1
x₁*x₂=c x₁+x₂=-b,
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Maratga1
обьясни!!!!
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Answers & Comments
Verified answer
Ax²+bx+c=0x₁,₂=(-b+/-√D)/2a=(-b+/-√(b²-4ac))/2a
x²-37x+27=0 a=1 b=-37 c=27 ⇒
x₁,₂=-(-37)+/-√((-37)²-4*1*27)/2*1=(37+/-√1261)/2 ⇒
x₁=(37+√1261)/2 x₂=(37-√1261)/2.
x2-3x+2=0
D=√(3²-4*1*2)=√(9-8)=√1=1
x₁,₂=(-(-3)+/-1)2*1=(3+/-1)/2
x₁=(3+1)/2=4 x₂=(3-1)/2=1
x₁*x₂=c x₁+x₂=-b,