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AlexMiller666
@AlexMiller666
August 2022
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Объясните срочно!
√56-x=-x
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m11m
Verified answer
ОДЗ:
56-x≥0 -x≥0
-x≥ -56 x≤0
x≤ 56
x∈(-∞; 0]
(√(56-x))² = (-x)²
56-x=x²
-x² -x+56=0
x²+x-56=0
D=1+224=225
x₁ = (-1-15)/2 = -8
x₂ = (-1+15)/2 = 7 - не подходит по ОДЗ.
Ответ: -8
3 votes
Thanks 5
AlexMiller666
x1,2= -b+- √D/2a сделай так пожалуйста
AlexMiller666
эйй
m11m
x1= (-1 -√225)/2*1 = (-1-15)/2= -8
x2=(-1+√225)/2*1=(-1+15)/2=7
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Answers & Comments
Verified answer
ОДЗ:56-x≥0 -x≥0
-x≥ -56 x≤0
x≤ 56
x∈(-∞; 0]
(√(56-x))² = (-x)²
56-x=x²
-x² -x+56=0
x²+x-56=0
D=1+224=225
x₁ = (-1-15)/2 = -8
x₂ = (-1+15)/2 = 7 - не подходит по ОДЗ.
Ответ: -8
x2=(-1+√225)/2*1=(-1+15)/2=7