Ответ:
x1 = +-π/6 + 2πn, n ∈ Z; x2 = (-1)^k*(-π/3) + πk, k ∈ Z
Объяснение:
1)
x1 = +-π/6 + 2πn, n ∈ Z
2)
x2 = (-1)^k*(-π/3) + πk, k ∈ Z
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Answers & Comments
Ответ:
x1 = +-π/6 + 2πn, n ∈ Z; x2 = (-1)^k*(-π/3) + πk, k ∈ Z
Объяснение:
1)
x1 = +-π/6 + 2πn, n ∈ Z
2)
x2 = (-1)^k*(-π/3) + πk, k ∈ Z