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$\frac{ \sqrt{ \sqrt{10}-12 }* \sqrt{ \sqrt{10}+12} }{ \sqrt{24} }= \\ \\ = \frac{ \sqrt{( \sqrt{10}-2)( \sqrt{10}+2) } }{ \sqrt{24} }= \\ \\ = \frac{ \sqrt{10-4} }{ \sqrt{24} } = \\ \\ = \frac{ \sqrt{6} }{ \sqrt{24} } = \\ \\ = \frac{ \sqrt{6} }{2 \sqrt{6} }= \\ \\ = \frac{1}{2}= \\ \\ =0,5$

Ответ: 0,5

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bertain

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$\frac{ \sqrt{ \sqrt{10}-2* \sqrt{10}+2 } }{ \sqrt{24} }= \frac{ \sqrt{10-4} } \sqrt{24} } = \frac{ \sqrt{6} }{ \sqrt{24} } = \sqrt{ \frac{6}{24} } = \sqrt{ \frac{1}{4} } = \frac{1}{2}$ = 0,5
Ответ: 0,5

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