1)2C5H10O4+11O2= 10CO2+10H2O

        1                                    5

2)C6H12O6+6O2 = 6CO2 + 6H2O

            1                         6

Пусть n(C5H10O4)= "х" моль, тогда

n(CO2)=(7x)моль;

n(СO2) в 1) =(7x :16)*10=4,375x;

n(C5H10O4)=4,375x/5=0,875x;

m(C5H10O4)=0,875x*134=117,25x

n(CO2) в 2) =(7x :16)*6=2,625x;

n(C6H12O6)=2,625x/6=0,4375x;

m(C6H12O6)=0,4375x*180=78,75x;

W(C5H10O4)= 117,25x/(117,25+78,75x)=0,5982(59,82%).