ab+c-ab-b-ab+c=2c-ab-b
2c-(3c+(2c-(c+1))+3)=2c-(3c+(2c-c-1)+3)=2c-(3c+2c-c-1)+3=2c-(4c-1)+3=2c-4c+1+3=-2c+4
n=(1;11)
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ab+c-ab-b-ab+c=2c-ab-b
2c-(3c+(2c-(c+1))+3)=2c-(3c+(2c-c-1)+3)=2c-(3c+2c-c-1)+3=2c-(4c-1)+3=2c-4c+1+3=-2c+4
n=(1;11)