4х^2-х+с=0
Х1=1
4*(1)^2 - 1 + с = 0
4 - 1 + с=0
С = -3 - свободный член
4х^2 - х - 3 = 0
D = b^2 - 4ac = (-1)^2 - 4*4*(-3)= 1+48 = 49
X1= (-b+VD)/(2a) = (1 +7)/(2*4)=1
X2=(-b -VD)/(2a) = (1 - 7)/(2*4) = -6/8= -3/4
Ответ: х2= -3/4, с= -3
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4х^2-х+с=0
Х1=1
4*(1)^2 - 1 + с = 0
4 - 1 + с=0
С = -3 - свободный член
4х^2 - х - 3 = 0
D = b^2 - 4ac = (-1)^2 - 4*4*(-3)= 1+48 = 49
X1= (-b+VD)/(2a) = (1 +7)/(2*4)=1
X2=(-b -VD)/(2a) = (1 - 7)/(2*4) = -6/8= -3/4
Ответ: х2= -3/4, с= -3