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murillo1601
@murillo1601
July 2022
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Один из корней уравнения x2 − 13x + q = 0 равен 1. Найдите другой корень и коэффициент q.
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ludmilagena
Verified answer
X²-13x+q=0 x=1
1-13+q=0 q=12
x²-13x+12=0
D=169-48=121 √D=11
x1=(13+11)/2=12
x2=(13-11)/2=1 ответ q=12 x=7
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ludmilagena
ответ: q=12 x=12
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Answers & Comments
Verified answer
X²-13x+q=0 x=11-13+q=0 q=12
x²-13x+12=0
D=169-48=121 √D=11
x1=(13+11)/2=12
x2=(13-11)/2=1 ответ q=12 x=7